Feature (key: gender) cannot have rank 0

General Discussion
#1

Hello guys,
Can you help me?
I don’t know, why I am getting this error.

import pandas as pd
import tensorflow as tf

def main():
dataframe = pd.read_csv(“music.csv”)
print(dataframe.columns)
y_label = dataframe.pop(“age”)

CATEGORICAL_COLUMNS = ["genre"]
NUMERIC_COLUMNS = ["gender"]

feature_columns = []
for feature_name in CATEGORICAL_COLUMNS:
    vocabulary = dataframe[feature_name].unique()
    feature_columns.append(tf.feature_column.categorical_column_with_vocabulary_list(feature_name, vocabulary))

for feature_name in NUMERIC_COLUMNS:
    feature_columns.append(tf.feature_column.numeric_column(feature_name, dtype=tf.float32))

def make_input_fn(data_df, label_df, num_epochs=10, shuffle=True, batch_size=32):
    def input_function():
        ds = tf.data.Dataset.from_tensor_slices((dict(data_df), label_df))
        if shuffle:
            ds.shuffle(1000)
        ds.batch(batch_size).repeat(num_epochs)
        return ds
    return input_function

print(feature_columns)

data_totrain_fn = make_input_fn(dataframe, y_label)
normal = make_input_fn(data_df=dataframe, label_df=y_label, batch_size=1, num_epochs=1, shuffle=False)
linear_est = tf.estimator.LinearClassifier(feature_columns=feature_columns)
linear_est.train(data_totrain_fn)
result = linear_est.evaluate(normal)
print(result['accuracy'])

if name == “main”:
main()

#3

This needs more info…

  1. Where does the error occur?
  2. Can you show some of your dataset (perhaps the top 10 rows?)

Also, does this help?

#5

You should assign back to the dataset (i.e ds) in input_function as described below

def make_input_fn(data_df, label_df, num_epochs=10, shuffle=True, batch_size=32):
  def input_function():
    ds = tf.data.Dataset.from_tensor_slices((dict(data_df), label_df))
    ds.batch(10)
    if shuffle:
      ds = ds.shuffle(1000)
    ds = ds.batch(batch_size).repeat(num_epochs)
    return ds
  return input_function

If you struck again. Please share the music.csv dataset to replicate the issue. Thank you.